从您的要求,如果你的文件的名字总是遵循相同的风格,我想你可以用这个流程做到这一点: 1.定义Direcroty /地图这是一个 2.获取的所有文件,然后循环文件&与分裂的文件名“ - ” &以秒为日期,然后添加到目录/图 3.将其不满足条件进行
$maps = New-Object 'system.collections.generic.dictionary[[string],[system.collections.generic.list[string]]]';
$list = New-Object 'system.collections.generic.list[string]';
$files = ("17988000412767900-20170402-T",
"17988000412770804-20170402-T",
"17988000412773204-20170402-T",
"17988000412792005-20170402-T",
"17988000412794300-20170402-T",
"17991325988242500-20170403-C",
"17991325988242800-20170403-C",
"17991325988243000-20170403-C",
"17991325988245000-20170403-C",
"17991325988245200-20170403-C",
"17992327574130910-20170404-T",
"17992327574131100-20170404-T",
"17992327574145005-20170404-T",
"17992327574145209-20170404-T",
"17992327574169106-20170404-T",
"17993057054385600-20170405-T",
"17993326857390200-20170405-R",
"17993327575638604-20170405-T",
"17993327575676304-20170405-T",
"17993327575835705-20170405-T",
"17993327575844703-20170405-T",
"17997018695202606-20170409-T",
"17998001450000100-20170409-C",
"17998001450001000-20170409-C",
"17998057920002100-20170409-R",
"17998119423714112-20170410-T",
"17998119423728401-20170410-T",
"17998282230003400-20170409-R",
"17998297810002500-20170409-R",
"17998327575543207-20170410-T",
"17998327575543708-20170410-T",
"17998327575546104-20170410-T",
"17998327575547600-20170410-T",
"17998327575591805-20170410-T");
$files | %{
$date = $_.Split('-')[1];
if($maps.Keys.Contains($date)){
$maps[$date].Add($_);
}
else{
$maps.Add($date, $list);
$maps[$date].Add($_);
}
}
输出将所有文件:
Key : 20170402
Value : {17988000412767900-20170402-T, 17988000412770804-20170402-T, 17988000412773204-20170402-T, 17988000412792005-20170402-T...}
Key : 20170403
Value : {17988000412767900-20170402-T, 17988000412770804-20170402-T, 17988000412773204-20170402-T, 17988000412792005-20170402-T...}
Key : 20170404
Value : {17988000412767900-20170402-T, 17988000412770804-20170402-T, 17988000412773204-20170402-T, 17988000412792005-20170402-T...}
Key : 20170405
Value : {17988000412767900-20170402-T, 17988000412770804-20170402-T, 17988000412773204-20170402-T, 17988000412792005-20170402-T...}
Key : 20170409
Value : {17988000412767900-20170402-T, 17988000412770804-20170402-T, 17988000412773204-20170402-T, 17988000412792005-20170402-T...}
Key : 20170410
Value : {17988000412767900-20170402-T, 17988000412770804-20170402-T, 17988000412773204-20170402-T, 17988000412792005-20170402-T...}
然后您可以订购$ map并循环它的所有文件的值&将它们移出。
您好,欢迎堆栈溢出!请[编辑](http://stackoverflow.com/posts/43530400/edit)您的问题,向我们提供显示您尝试过的代码。一定要包括你收到的任何错误,或解释它如何不能达到你的预期。 – TheMadTechnician