嵌套的循环在bash

Question

在从那里我运行bash脚本的目录，

目录保存在变量：

ScriptDir=`pwd` 

我有以下文件：

B3LYP_BOTTOM_FRAGMENT 
B3LYP-D3_BOTTOM_FRAGMENT 
PBE_BOTTOM_FRAGMENT 
LDA_BOTTOM_FRAGMENT 
PBE-D3_BOTTOM_FRAGMENT 
PBE0_BOTTOM_FRAGMENT 
PBE0-DC_BOTTOM_FRAGMENT 

254.186305_TOP_FRAGMENT.d12 
252.050453_TOP_FRAGMENT.d12 
249.921810_TOP_FRAGMENT.d12 
247.812353_TOP_FRAGMENT.d12 
245.699603_TOP_FRAGMENT.d12 
243.644688_TOP_FRAGMENT.d12 
241.581529_TOP_FRAGMENT.d12 
239.554134_TOP_FRAGMENT.d12 
237.467646_TOP_FRAGMENT.d12 
235.473555_TOP_FRAGMENT.d12 

这些文件可以分为两个不同的变量：DIRS和FOLDERS

DIRS=" 
PBE-D3 
PBE 
B3LYP 
B3LYP-D3 
PBE0 
PBE0-DC 
LDA 
" 
FOLDERS=" 
237.467646 
239.554134 
241.581529 
243.644688 
245.699603 
247.812353 
249.921810 
252.050453 
254.186305 
235.473555 
" 

鉴于此路径：/path/to/target，如果我遍历DIRS（$i）和FOLDERS（$j），我想用下面落得：

ls -lrth /path/to/target/PBE-D3/scaling_volumes/237.467646 

237.467646_TOP_FRAGMENT.d12   # j = 1 on FOLDERS 
PBE-D3_BOTTOM_FRAGMENT    # i = 1 on DIRS 
237.467646.d12 

# where `237.467646.d12` is the result of doing: 
# cat 237.467646_TOP_FRAGMENT.d12 PBE-D3_BOTTOM_FRAGMENT > 237.467646.d12 

ls -lrth /path/to/target/PBE-D3/scaling_volumes/239.554134 

239.554134_TOP_FRAGMENT.d12   # j = 2 on FOLDERS 
PBE-D3_BOTTOM_FRAGMENT    # i = 1 on DIRS 
239.554134.d12 

ls -lrth /path/to/target/PBE-D3/scaling_volumes/241.581529 

241.581529_TOP_FRAGMENT.d12   # j = 3 on FOLDERS 
PBE-D3_BOTTOM_FRAGMENT    # i = 1 on DIRS 
241.581529.d12 

# and so on... 
# In other words, in this iteration, all the `j`th `FOLDERS` for a given `j`th `DIR` 

# For the second `DIR`, again the 1st `FOLDER`: 
ls -lrth /path/to/target/PBE/scaling_volumes/237.467646 

237.467646_TOP_FRAGMENT.d12   # j = 1 on FOLDERS 
PBE_BOTTOM_FRAGMENT     # i = 2 on DIRS 
237.467646.d12 

# and so on 

我写了下面的脚本：

DIRS=" 
PBE-D3 
PBE 
B3LYP 
B3LYP-D3 
PBE0 
PBE0-DC 
LDA 
" 
FOLDERS=" 
237.467646 
239.554134 
241.581529 
243.644688 
245.699603 
247.812353 
249.921810 
252.050453 
254.186305 
235.473555 
" 

ScriptDir=`pwd` 

for i in ${DIRS}; do 

cd /path/to/target/$i 

rm -Rf scaling_volumes 
mkdir scaling_volumes 

cd scaling_volumes 

for j in ${FOLDERS}; do 
    rm -Rf ${j} 
    mkdir ${j} 
    cd $ScriptDir 

    cp -avr ${j}_TOP_FRAGMENT.d12 /path/to/target/$i/scaling_volumes/${j} 

    cp -avr ${i}_BOTTOM_FRAGMENT /path/to/target/$i/scaling_volumes/${j} 

    cd /path/to/target/$i/scaling_volumes/${j} 

    cat ${j}_TOP_FRAGMENT.d12 ${i}_BOTTOM_FRAGMENT > ${j}.d12 

    cd $ScriptDir 

    done 

done 

出于某种原因，我得到的是：

ls -lrth /path/to/target/PBE-D3/scaling_volumes 

235.473555 # Only the last FOLDER has been created 

或：

ls -lrth /path/to/target/PBE/scaling_volumes 

235.473555 # Only the last FOLDER has been created 

其中只有最后j日FOLDER创建

Answer 1

• 快速失败，之后cd和mkdir命令添加|| exit 1
• 避免cd使用它只有在必要的时候，因为路径是绝对

另外，脚本目录可能与pwd（当前工作目录）不同，例如，如果从另一个目录调用脚本。

Answer 2

继@choroba的很好的建议，我设法通过创建一个

scaling=`pwd` 

变量来解决问题，而就在for j in ${FOLDERS}循环之前放置，并结束该循环与

cd $scaling 

但是，我对@Nahuel Fouilleul建议的|| exit 1方法非常感兴趣，但恐怕我不知道从哪里开始。

ScriptDir=`pwd` 

for i in ${DIRS}; do 

cd /home/david/Trabajo/structures/Trial_for_double_for_loop_in_bash/pob_TZVP/Calcite_I/$i 

rm -Rf scaling_volumes_from_117.743646 
mkdir scaling_volumes_from_117.743646 

cd scaling_volumes_from_117.743646 

scaling=`pwd` 

for j in ${FOLDERS}; do 
    rm -Rf ${j} 
    mkdir ${j} 
    cd $ScriptDir 

    cp -avr ${j}_TOP_FRAGMENT.d12 /home/david/Trabajo/structures/Trial_for_double_for_loop_in_bash/pob_TZVP/Calcite_I/$i/scaling_volumes_from_117.743646/${j} 

    cp -avr ${i}_BOTTOM_FRAGMENT /home/david/Trabajo/structures/Trial_for_double_for_loop_in_bash/pob_TZVP/Calcite_I/$i/scaling_volumes_from_117.743646/${j} 

    cd /home/david/Trabajo/structures/Trial_for_double_for_loop_in_bash/pob_TZVP/Calcite_I/$i/scaling_volumes_from_117.743646/${j} 

    cat ${j}_TOP_FRAGMENT.d12 ${i}_BOTTOM_FRAGMENT > ${j}.d12 

    cd $scaling 

    done 

done