使用C＃中的fileuploadControl将数据保存到数据库＃

我在窗体中有多个文件上传控件。我试图上传尽可能多的用户想要数据库的文件，并用下拉菜单选择附件的类型。我能够将文件保存到数据库，但我的数据全部为0（0x0000000000000000000000000000000000000000 ... 00）。当我试图检索文件，当用户点击文件链接时，我得到一个错误，syas“无法加载PDF文档”。使用C＃中的fileuploadControl将数据保存到数据库＃

这里是我的代码它保存到数据库：

public void getDynamicFilesFromUploadedFileList(int wWireTransferID, int wUserID) 
    { 
     if (GridView1.Rows.Count > 0) 
     { 
      foreach (GridViewRow grow in GridView1.Rows) 
      { 
       try 
       { 
        FileUpload fileuploadControl = new FileUpload(); 
        fileuploadControl = (FileUpload)grow.FindControl("fUpControl"); 

        DropDownList drpFileType = new DropDownList(); 
        drpFileType = (DropDownList)grow.FindControl("ddlFileType"); 
        Guid newID = Guid.NewGuid(); 

        if (fileuploadControl.HasFile) 
        { 
         //I believe here is my mistake 
         Byte[] fileData = new Byte[fileuploadControl.PostedFile.ContentLength]; 

         new MRSManager().InsertWTDocument(wWireTransferID, 
          fileuploadControl.FileName, 
          drpFileType.SelectedValue.Trim(), 
          fileuploadControl.PostedFile.ContentType, 
          System.IO.Path.GetExtension(fileuploadControl.FileName), 
          fileuploadControl.PostedFile.ContentLength.ToString(), 
          fileData, 
          wUserID, 
          newID); 
        } 
        else 
        { 
         string m = "No File! "; 
        } 
       } 
       catch (Exception Exp) 
       { 
        string msg = Exp.Message.ToString(); 
       } 
      } 
     } 
    }

这是我如何尝试检索该文件的代码。

protected void Page_Load(object sender, EventArgs e) 
    { 
     // Get the file id from the query string 
     string id = Request.QueryString["ID"]; 

     // Get the file from the database 
     DataTable file = GetAFile(id); 
     DataRow row = file.Rows[0]; 

     string name = (string)row["FileName"]; 
     string contentType = (string)row["ContentType"]; 
     Byte[] data = (Byte[])row["Data"]; 

     Response.Clear(); 
     Response.ClearContent(); 
     Response.ClearHeaders(); 
     // Send the file to the browser 
     Response.AddHeader("Content-type", contentType); 
     Response.AddHeader("Content-Disposition", "inline; filename=" + name); 
     Response.Buffer = true; 
     Response.BinaryWrite(data); 
     Response.Flush(); 
     Response.Close(); 
     Response.End(); 
    } 

    // Get a file from the database by ID 
    public static DataTable GetAFile(string id) 
    { 
     DataTable file = new DataTable(); 
     string sSQL = string.Format("SELECT * FROM tblWireTransferDocuments WHERE FileID = '{0}'", id); 
     file = SqlHelper.ExecuteDataset(DBConnection.GetConnectionString(), CommandType.Text, sSQL, null).Tables[0]; 
     return file; 
    } 
}

}

来源

2016-09-19 S5498658

检查此问题http://stackoverflow.com/questions/2579373/saving-any-file-to-in-the-database-just-convert-it-to-a-byte-array – DanielVorph

你说得对

//I believe here is my mistake 
Byte[] fileData = new Byte[fileuploadControl.PostedFile.ContentLength];

你只创建FILEDATA，但没有填充它。你应该使用fileuploadControl.FileContent来填充fileData。

来源

2016-09-19 23:01:15 steryd

您可以创建流和从它读取。使用（System.IO.Stream myStream = fileuploadControl.FileContent） { myStream.Read（fileData，0，fileuploadControl.PostedFile.ContentLength）; } – steryd

感谢它的工作 – S5498658

使用C＃中的fileuploadControl将数据保存到数据库＃

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