翻转的列表结构的列表中的同一项目的具体位置

Question

我有以下数据结构：

pool = [[[0,0,0,0,0,0,0,0],"ze","Zero"], 
[[0,0,3,0,3,0,0,0],"bd","BasicDilemma"], 
[[0,0,3,2,3,0,0,2],"lk","LowLock"], 
[[0,1,3,2,0,3,1,2],"DlCo",""], 
[[0,1,3,2,0,3,2,1],"DlPc",""], 
[[0,1,3,2,1,3,0,2],"DlAs",""], 
[[0,1,3,2,1,3,2,0],"DlHa",""], 
[[0,1,3,2,2,3,0,1],"DlSh",""], 
[[0,1,3,2,2,3,1,0],"DlNc",""]] 

def ListFlip (pool): 
    for game in range (0, len(pool)): 
     game[0][2], game[0][3] = game[0][3], game[0][2] 
     game[0][6], game[0][7] = game[0][7], game[0][6] 
    return (pool) 

我需要翻转在每个项目中列出，只是数值的这个列表特定索引位置。

的结构将是：

[0,1,2,3,4,5,6,7] -> [0,1,3,2,4,5,7,6] 

所以对于所有的项目，我需要翻转位置[2] and [3]，并[6] and [7]

例如：

[[0,1,3,2,0,3,1,2],"DlCo",""] -> [[0,1,2,3,0,3,2,1],"DlCo",""] 

我认为这将做它的方式，但它不工作。有谁知道我做错了什么？

谢谢！

Answer 1

这条线：

for game in range (0, len(pool)): 

应该是：

for game in pool: 

随着第一只获得在游泳池每场比赛的索引，所以索引game[0][2]无效这里。

你的代码工作现在罚款：

pool = [[[0,0,0,0,0,0,0,0],"ze","Zero"], 
     [[0,0,3,0,3,0,0,0],"bd","BasicDilemma"], 
     [[0,0,3,2,3,0,0,2],"lk","LowLock"], 
     [[0,1,3,2,0,3,1,2],"DlCo",""], 
     [[0,1,3,2,0,3,2,1],"DlPc",""], 
     [[0,1,3,2,1,3,0,2],"DlAs",""], 
     [[0,1,3,2,1,3,2,0],"DlHa",""], 
     [[0,1,3,2,2,3,0,1],"DlSh",""], 
     [[0,1,3,2,2,3,1,0],"DlNc",""]] 

def ListFlip(pool): 
    for game in pool: 
     game[0][2], game[0][3] = game[0][3], game[0][2] 
     game[0][6], game[0][7] = game[0][7], game[0][6] 

    return pool 

print(ListFlip(pool)) 

，输出：

[[[0, 0, 0, 0, 0, 0, 0, 0], 'ze', 'Zero'], 
[[0, 0, 0, 3, 3, 0, 0, 0], 'bd', 'BasicDilemma'], 
[[0, 0, 2, 3, 3, 0, 2, 0], 'lk', 'LowLock'], 
[[0, 1, 2, 3, 0, 3, 2, 1], 'DlCo', ''], 
[[0, 1, 2, 3, 0, 3, 1, 2], 'DlPc', ''], 
[[0, 1, 2, 3, 1, 3, 2, 0], 'DlAs', ''], 
[[0, 1, 2, 3, 1, 3, 0, 2], 'DlHa', ''], 
[[0, 1, 2, 3, 2, 3, 1, 0], 'DlSh', ''], 
[[0, 1, 2, 3, 2, 3, 0, 1], 'DlNc', '']]