我开始通过观看youtube上的教程(phpacademy)来构建oop登录/注册系统,我得到了一分,代码无法工作。我检查了几次,仍然没有。数据库创建和工作很好,我有一个用户在db(用户)-alex。 如果有人可以看到我做错了什么,请帮助我:)PHP OOP登录/注册系统
我希望我解释我的问题是正确的,我得到的错误是:“致命错误:调用一个非对象的成员函数count()在C:\ XAMPP \ htdocs中\ oopLogin \的index.php第7" 行
db.php中
<?php
class DB {
private static $_instance = null;
private $_pdo,
$_query,
$_error = false,
$_results,
$_count = 0;
private function __construct() {
try {
$this->_pdo = new PDO('mysql:host=' . Config::get('mysql/host') . ';dbname=' . Config::get('mysql/db'), Config::get('mysql/username'), Config::get('mysql/password'));
} catch(PDOException $e) {
die($e->getMessage());
}
}
public static function getInstance() {
if(!isset(self::$_instance)) {
self::$_instance = new DB();
}
return self::$_instance;
}
public function query($sql, $params = array()) {
$this->_error = false;
if($this->_query = $this->_pdo->prepare($sql)) {
$x = 1;
if(count($params)) {
foreach($params as $param) {
$this->_query->bindValue($x, $param);
$x++;
}
}
if($this->_query->execute()) {
$this->_results = $this->_query->fetchAll(PDO::FETCH_OBJ);
$this->_count = $this->_query->rowCount();
}
else {
$this->_error = true;
}
}
return $this;
}
public function action($action, $table, $where = array()) {
if(count($where) === 3){
$operators = array('=', '>', '<', '>=', '<=');
$field = $where[0];
$operator = $where[1];
$value = $where[2];
if(in_array($operator, $operators)) {
$sql = "($action) FROM ($table) WHERE ($field) ($operator) ?";
if(!$this->query($sql, array($value))->error()) {
return $this;
}
}
}
return false;
}
public function get($table, $where) {
return $this->action('SELECT *', $table, $where);
}
public function delete($table, $where) {
return $this->action('DELETE', $table, $where);
}
public function results() {
return $this->_results;
}
public function error() {
return $this->_error;
}
public function count() {
return $this->_count;
}
}
的index.php
<?php
require_once 'core/init.php';
$user = DB::getInstance()->get('users', array('username', '=', 'alex'));
if(!$user->count()) {
echo 'No user';
} else {
foreach($user->results() as $user) {
echo $user->username, '<br>';
}
}
'计数()'是在'DB'类中的方法,而不是在你的结果。 – DanFromGermany 2014-09-22 10:47:30
考虑@DanFromGermany的评论是正确的。我不确定'$ sql =“($ action)FROM($ table)WHERE($ field)($ operator)?”;'因括号而工作。 – jbrtrnd 2014-09-22 10:51:41
你在你的DB类中使用return $ this,检查$ user currectly返回,vardump($ user);之前如果帮助你!它看起来是虚假的而不是$ this – 2014-09-22 10:52:22