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我有一个名为box的实体。每个包含一些参数的参数对于许多唯一的ID都是相同的。唯一ID只是数字，并没有任何其他角色。 所以我创建它们作为postgresql和Java中的文本数组，我将它们作为ArrayList并使用自定义用户类型进行映射。 package com.geniedoc.utils;在postgresql中包含/ in文本数组的Hibernate条件
import java.io.Serializable;
import java.sql.Array;
import java.sql.Connection;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Types;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Iterator;
import java.util.List;
import java.util.StringTokenizer;
import org.hibernate.HibernateException;
import org.hibernate.engine.spi.SessionImplementor;
import org.hibernate.usertype.UserType;
public class PostgresTextArrayType implements UserType {
protected static final int[] SQL_TYPES = {Types.ARRAY};
public Class<String> returnedClass() {
return String.class;
}
public final int[] sqlTypes() {
return SQL_TYPES;
}
@Override
public Object nullSafeGet(ResultSet resultSet, String[] names,
SessionImplementor arg2, Object arg3)
throws HibernateException, SQLException {
List<String> list = null;
String nameVal = resultSet.getString(names[0]);
if (nameVal != null) {
nameVal = nameVal.substring(1,nameVal.length()-1);
list = new ArrayList<>();
StringTokenizer tokenizer = new StringTokenizer(nameVal, ",");
while (tokenizer.hasMoreElements()) {
String val = (String) tokenizer.nextElement();
list.add(val);
}
}
return list;
}
@Override
public void nullSafeSet(PreparedStatement statement, Object value, int index,
SessionImplementor arg3) throws HibernateException,
SQLException {
Connection connection = statement.getConnection();
if (value == null) {
statement.setNull(index, SQL_TYPES[0]);
} else {
System.out.println("statement>>>>"+statement);
System.out.println("value>>>>"+ value);
System.out.println("index>>>>"+index);
@SuppressWarnings("unchecked")
ArrayList<String> parameter=new ArrayList<>();
if(value instanceof Array)
{ parameter=(ArrayList<String>) value;
}else
{
parameter.add((String) value);
}
ArrayList<String> list=parameter;
String[] castObject = Arrays.copyOf(list.toArray(), list.toArray().length, String[].class);
Array array = connection.createArrayOf("text", castObject);
statement.setArray(index, array);
System.out.println("statement>>>>"+statement);
}
}
@Override
public final Object deepCopy(final Object value) throws HibernateException {
return value;
}
@Override
public final boolean isMutable() {
return false;
}
@Override
public final Object assemble(final Serializable serializable, final Object arg1)
throws HibernateException {
return serializable;
}
@Override
public final Serializable disassemble(final Object o) throws HibernateException {
return (Serializable) o;
}
@Override
public final boolean equals(final Object x, final Object y) throws HibernateException {
if (x == y) {
return true;
} else if (x == null || y == null) {
return false;
} else {
return x.equals(y);
}
}
@Override
public final int hashCode(final Object x) throws HibernateException {
return x.hashCode();
}
@Override
public final Object replace(
final Object original,
final Object target,
final Object owner) throws HibernateException {
return original;
}
private String serialize(List<String> list) {
StringBuilder strbul = new StringBuilder();
Iterator<String> iter = list.iterator();
strbul.append("{");
while (iter.hasNext()) {
strbul.append(iter.next());
if (iter.hasNext()) {
strbul.append(",");
}
}
strbul.append("}");
return strbul.toString();
}
}
这是我的休眠条件： -
Session session=getSession();
Criteria criteria=session.createCriteria(Box.class);
criteria.add(Restrictions.in("unique_id", unique_id));
return (Unit)criteria.uniqueResult();
我需要包含一个特定的独特id.But它不工作的框。 仅当我在数据库中的文本数组中有一个值时才返回结果。 但是，如果我有在数据库中的多个值，它不显示任何结果。
任何帮助表示赞赏。