如何查询以获得此结果？

Question

3表是有，一个是学生，第二个是主体和第三个是马克表。

student table: 
    student_id student_name 

subject table: 
    subject_id subject_name 

marks table: 
    student_id subject_id marks 

我写此查询：

select student_id, subject_id, marks, RANK() over (partition by subject_id order by marks desc rank 
from marks order by student_id, subject_id; 

它给正确的结果，但我想到位student_id数据和subject_id的student_name和SUBJECT_NAME。

如何加入这些表？ 谢谢。

Answer 1

只需添加一对夫妇的join条款：

SELECT student_name, subject_name, marks, 
     RANK() OVER (PARTITION BY subject_name ORDER BY marks DESC) rk 
FROM  marks 
JOIN  student ON marks.student_id = student.student_id 
JOIN  subject ON marks.subject_id = subject.subject_id 
ORDER BY student_name, subject_name 

Answer 2

这可以通过简单的做加盟

select student_name, subject_name, marks, RANK() over (partition by subject_id order by marks desc) rank 
    from marks 
    inner join student on mark.student_id=student.student_id 
    inner join subject on mark.subject_id=subject.subject_id 
    order by student_id, subject_id;