2012-02-21 71 views
0

我使用PHP上传文件,然后我想抓住它的URL,以便我可以将其添加到数据库。我怎样才能将新文件的URL导入一个我可以用来通过MySQL插入的变量?PHP文件上传..检索URL

<?php 
// Configuration - Your Options 
    $allowed_filetypes = array('.jpg','.gif','.bmp','.png'); // These will be the types  of file that will pass the validation. 
    $max_filesize = 524288; // Maximum filesize in BYTES (currently 0.5MB). 
    $upload_path = './files/'; // The place the files will be uploaded to (currently a 'files' directory). 

$filename = $_FILES['userfile']['name']; // Get the name of the file (including file extension). 
$ext = substr($filename, strpos($filename,'.'), strlen($filename)-1); // Get the extension from the filename. 

// Check if the filetype is allowed, if not DIE and inform the user. 
if(!in_array($ext,$allowed_filetypes)) 
    die('The file you attempted to upload is not allowed.'); 

// Now check the filesize, if it is too large then DIE and inform the user. 
if(filesize($_FILES['userfile']['tmp_name']) > $max_filesize) 
    die('The file you attempted to upload is too large.'); 

// Check if we can upload to the specified path, if not DIE and inform the user. 
if(!is_writable($upload_path)) 
    die('You cannot upload to the specified directory, please CHMOD it to 777.'); 

// Upload the file to your specified path. 
if(move_uploaded_file($_FILES['userfile']['tmp_name'],$upload_path . $filename)) 
    echo 'Your file upload was successful, view the file <a href="' . $upload_path . $filename . '" title="Your File">here</a>'; 
// It worked. 
    else 
    echo 'There was an error during the file upload. Please try again.'; // It failed :(. 

?> 

回答

2
元素

您网站上的文件,以一个位置移动:

move_uploaded_file($_FILES['userfile']['tmp_name'],$upload_path . $filename)

也就是说$upload_path . $filename是你的相对URL到文件。您可以预先安排您的网站网址以获取绝对网址。

0

实际上,在php上传的文件存储在一个临时的地方/目录进行进一步处理。
所以可以很好地得到它的从目前的网址,

$_FILES["file"]["tmp_name"] 


这是你给它保存文件的副本在你的服务器位置的URL。
如果要指定通过你的PHP应用程序上传的文件默认loaction,
你可以在php.ini文件中定义它 - >编辑 - > upload_tmp_dir到您的愿望
希望这有助于:)

+0

tmp-location在上传完成后被删除,因此无价值。看到husbas的解决方案的答案。 – OptimusCrime 2012-02-21 07:39:15

+0

@OptimusCrime都是相同的$ _FILES [“文件”] [“tmp_name”]复制它只是一种方式。这是一个简单的问题和简单的答案。 – 2012-02-21 08:27:26