我正在使用aws在Java中编写webservice,并且在许多方法中,我需要有一个try catch块,它可以实际记录每个公开方法的执行过程中可能发生的任何错误。如何避免重复尝试块
@WebMethod(operationName = "listingBucket")
public String listingBucket() {
String message = "";
try {
message = "Listing buckets";
for (Bucket bucket : s3.listBuckets()) {
message += " - " + bucket.getName();
}
} catch (AmazonServiceException ase) {
message += "Caught an AmazonServiceException, which means your request made it "
+ "to Amazon S3, but was rejected with an error response for some reason.";
message += "Error Message: " + ase.getMessage();
message += "HTTP Status Code: " + ase.getStatusCode();
message += "AWS Error Code: " + ase.getErrorCode();
message += "Error Type: " + ase.getErrorType();
message += "Request ID: " + ase.getRequestId();
} catch (AmazonClientException ace) {
message += "Caught an AmazonClientException, which means the client encountered "
+ "a serious internal problem while trying to communicate with S3, "
+ "such as not being able to access the network.";
message += "Error Message: " + ace.getMessage();
}
return message;
}
@WebMethod(operationName = "addObjectToBucket")
public String addObjectToBucket(String bucketName, String objectName, File file) throws IOException{
if (file == null){
file = createSampleFile();
}
String message = "";
try {
message += "Uploading a new object to S3 from a file\n";
s3.putObject(new PutObjectRequest(bucketName, objectName, file));
} catch (AmazonServiceException ase) {
message += "Caught an AmazonServiceException, which means your request made it "
+ "to Amazon S3, but was rejected with an error response for some reason.";
message += "Error Message: " + ase.getMessage();
message += "HTTP Status Code: " + ase.getStatusCode();
message += "AWS Error Code: " + ase.getErrorCode();
message += "Error Type: " + ase.getErrorType();
message += "Request ID: " + ase.getRequestId();
} catch (AmazonClientException ace) {
message += "Caught an AmazonClientException, which means the client encountered "
+ "a serious internal problem while trying to communicate with S3, "
+ "such as not being able to access the network.";
message += "Error Message: " + ace.getMessage();
}
return message;
}
如何避免重复此try catch块抛出使用这种东西的所有方法?
感谢您的帮助!
编辑:其实我修改了代码:
private String parseError(AmazonServiceException ase) {
String message;
message = "Caught an AmazonServiceException, which means your request made it "
+ "to Amazon S3, but was rejected with an error response for some reason.";
message += "Error Message: " + ase.getMessage();
message += "HTTP Status Code: " + ase.getStatusCode();
message += "AWS Error Code: " + ase.getErrorCode();
message += "Error Type: " + ase.getErrorType();
message += "Request ID: " + ase.getRequestId();
return message;
}
private String parseError(AmazonClientException ace) {
String message;
message += "Caught an AmazonClientException, which means the client encountered "
+ "a serious internal problem while trying to communicate with S3, "
+ "such as not being able to access the network.";
message += "Error Message: " + ace.getMessage();
return message;
}
@WebMethod(operationName = "listingBucket")
public String listingBucket() {
String message = "";
try {
message = "Listing buckets";
for (Bucket bucket : s3.listBuckets()) {
message += " - " + bucket.getName();
}
} catch (AmazonServiceException exc) {
message += parseError(exc);
} catch (AmazonClientException exc) {
message += parseError(exc);
}
return message;
}
更清晰哉! :)
我只是看看命令模式,看看我是否可以使用它的这种类型的应用程序。
您需要的Java 8 Lambda表达式干净地做到这一点。这是一个选择吗? –
注意:'message ='*替换*以前的值。你只需要做一次,并且不止一次地丢弃之前的值。 –
其实是的,我使用Java 8,我正在寻找Lambda,如果你有一个解决方案,我很好奇,看看它! :) – Slater