如何在SQL查询中显示多个表中的列？

Question

我试图显示从我的查询中有3个表中的一个列中的列，但我似乎无法弄清楚如何让它正常工作。无论我尝试什么，它似乎都不起作用。这似乎很容易，但也许我错过了一些非常简单的事情。以下是我有：

SELECT hpg.id_number, 
    hpg.id_description, 
    COUNT (hdd.number_of_games) games, 
    SUM (NVL (price, 0)) total, 
    SUM (number_of_food) food 
--I tried adding column here, but nothing seemed to work 
FROM (SELECT number_of_games, price, prints 
     FROM (hopeful_dog_hops) 
     WHERE status = 'Done') hdd, 
    (SELECT SUM (number_of_food) number_of_food, number_of_games 
      FROM hot_digity_dog 
     GROUP BY number_of_games) hdd1, 
    (SELECT id_description, sort_types, id_number 
     FROM (hot_pick_games) 
     WHERE disabled = 'TRUE' AND viewable_type = 'OK') hpg 
WHERE hdd.prints(+) = hpg.id_number 
    AND hdd.number_of_games = hdd1.number_of_games 
GROUP BY hpg.id_description, hpg.id_number, sort_types 
ORDER BY sort_types 

这个巨大的查询显示这些列：

ID_NUMBER ID_DESCRIPTION GAMES TOTAL FOOD 

我需要增加一个列：从hot_digity_dog表

TEST 

。

不要太担心所有事情的名称，但我只需要弄清楚我到底能够在查询中显示另一列。我试着将TEST添加到第一个SELECT语句中，但它给了我一个错误：“TEST：无效标识符”。

我知道查询的工作原理（没有添加TEST部分，所以它不能成为查询中的错误）。它必须是新增加的部分。

任何帮助将不胜感激。提前致谢。

这里是新列的查询：

SELECT hpg.id_number, 
    hpg.id_description, 
    COUNT (hdd.number_of_games) games, 
    SUM (NVL (price, 0)) total, 
    SUM (number_of_food) food, 
    hdd.TEST 
FROM (SELECT number_of_games, price, prints 
     FROM (hopeful_dog_hops) 
     WHERE status = 'Done') hdd, 
    (SELECT SUM (number_of_food) number_of_food, number_of_games 
      FROM hot_digity_dog 
     GROUP BY number_of_games) hdd1, 
    (SELECT id_description, sort_types, id_number 
     FROM (hot_pick_games) 
     WHERE disabled = 'TRUE' AND viewable_type = 'OK') hpg 
WHERE hdd.prints(+) = hpg.id_number 
    AND hdd.number_of_games = hdd1.number_of_games 
GROUP BY hpg.id_description, hpg.id_number, sort_types 
ORDER BY sort_types 

这里是列标题应该是什么样子：

ID_NUMBER ID_DESCRIPTION GAMES TOTAL FOOD TEST 

Answer 1

的问题是，你是不是从hot_digity_dog的选择外部查询。您可以从基于该表的AGGREGATE子查询中进行选择 - 您以别名hdd1作为别名的子查询。所以，目前尚不清楚如何你想添加那个列。 test完全由number_of_games决定？如果是，则可以将test添加到聚合子查询的select和group by子句中，然后可以在外部查询中选择它。

如果test不是由number_of_games确定，你要总结number_of_food由number_of_games和test为分组？如果是这样，再次在子查询中添加test到select和group by（但结果将单独由number_of_games分组）。

如果test不是由number_of_games确定，要通过组为number_of_games的总和，但要显示test无论如何，你可能需要使用分析sum()而不是总sum()。

这只是一个小例子，向您证明您发布的内容不足以让我们来帮助您。请提供（更多）更多细节 - 通过编辑原始问题，而不是在评论中。

Answer 2

我认为你只是缺少在HDD查询测试柱：

SELECT hpg.id_number, 
    hpg.id_description, 
    COUNT (hdd.number_of_games) games, 
    SUM (NVL (price, 0)) total, 
    SUM (number_of_food) food, 
    hdd.TEST 
FROM (SELECT number_of_games, price, prints, TEST 
     FROM (hopeful_dog_hops) 
     WHERE status = 'Done') hdd, 
    (SELECT SUM (number_of_food) number_of_food, number_of_games 
      FROM hot_digity_dog 
     GROUP BY number_of_games) hdd1, 
    (SELECT id_description, sort_types, id_number 
     FROM (hot_pick_games) 
     WHERE disabled = 'TRUE' AND viewable_type = 'OK') hpg 
WHERE hdd.prints(+) = hpg.id_number 
    AND hdd.number_of_games = hdd1.number_of_games 
GROUP BY hpg.id_description, hpg.id_number, sort_types 
ORDER BY sort_types