扩展数据库类

Question

我有一个数据库类：

<?php 

class dbConnect 
{ 
    var $strHost = ""; 
    var $strDatabase = ""; 
    var $strUser = ""; 
    var $strPassword = ""; 

    var $intLinkID = 0; 
    var $intQueryID = 0; 
    var $arrRecord = array(); 
    var $intRow; 

    var $intErrno = 0; 
    var $strError = ""; 

    function dbConnect() 
    { 
     $this->Connect(); 
    } 

    function dbHalt($strError) 
    { 
     $objError = new errorHandle(); 

     $objError->reportError("Database error: $strError", false); 
     $this->intErrno = mysql_errno($this->intLinkID); 
     $this->strError = mysql_error($this->intLinkID); 

     $strError = sprintf("MySQL Error: %s (%s)", $this->intErrno, $this->strError); 

     $objError->reportError($strError, true); 
    } 

    function Connect() 
    { 
     if (0 == $this->intLinkID) { 

      $this->intLinkID = mysql_connect($this->strHost, $this->strUser, $this->strPassword); 
      if (!mysql_select_db($this->strDatabase, $this->intLinkID)) { 
       $this->dbHalt("cannot use database " . $this->strDatabase); 
      } 

     } 

     if (!$this->intLinkID) { 
      $this->dbHalt("Database connection failed"); 
     } 


    } 
} 

class dbMain extends dbConnect 
{ 
// Database connection settings. 

// Dev server. 
    var $strHost = 'db_host_here'; 
    var $strUser = 'db_User_here'; 
    var $strPassword = 'db_password_here'; 
    var $strDatabase = 'db_name_here'; 
} 

此呼吁$objDB = new dbMain();

但我要的是动态设置数据库的详细信息在其他类（主CMS）时，工作正常例如：

$objDB = new dbMain($user, $pass, $dbname, $dbhost); 

Answer 1

使用类构造函数。传入值。

class dbMain 
{ 
    function __construct($strHost='db_host_here',$strUser='db_User_here',$strPassword='db_password_here',$strDatabase='db_name_here'){ 
     $this->strHost = $strHost; 
     $this->strUser = $strUser; 
     $this->strPassword = $strPassword; 
     $this->strDatabase = $strDatabase; 
    } 
}