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我有此数组:结合阵列相同的元素值,并让他们一起
[0] => Array
(
[userid] => 208
[username] => sara
[email] => [email protected]
)
[1] => Array
(
[userid] => 4
[username] => jack
[email] => [email protected]
)
[2] => Array
(
[userid] => 303
[username] => michael
[email] => [email protected]
)
[3] => Array
(
[userid] => 208
[username] => joe
[email] => [email protected]
)
[4] => Array
(
[userid] => 208
[username] => david
[email] => [email protected]
)
,我想这样的结果:
[0] => Array
(
[userid] => 208
[username1] => sara
[username2] => joe
[username3] => david
[email1] => [email protected]
[email2] => [email protected]
[email3] => [email protected]
)
[1] => Array
(
[userid] => 4
[username1] => jack
[email1] => [email protected]
)
[2] => Array
(
[userid] => 303
[username1] => michael
[email1] => [email protected]
)
我想array_combine,array_merge甚至array_unique有几个foreach加$ n ++;循环没有成功。更精确地说,我成功了,但改变了阵列的整个结构。
最好的实现,虽然$结果[$用户id = $用户ID;应该是$ result [$ userid] [“userid”] = $ userid;和$ index =(count($ result [$ userid]) - 1/2)+ 1;应该是$ index =((count($ result [$ userid]) - 1)/ 2)+ 1;和$ result [$ userid] ['email1'。 $ index] = $ value ['email'];应该是$ result [$ userid] ['email'。 $ index] = $ value ['email']; – 2013-04-25 16:29:07
你是对的。我更新了我的答案。 – 2013-04-25 16:31:12
最后我可以看到一些逻辑。没有阵列合并,结合和独特的需要。只是一个foreach和一个if。谢谢奥马尔和帕特里克。我吸取了教训。 – user1274113 2013-04-26 07:33:04