多边形的洞

Question

首先给那些想评论我的低接受率的人...即时新的，给我一个休息。

我说从本网站这个多边形代码： http://www.geocodezip.com/v3_polygon_example_donut.html

有一个问题，虽然，半径是不准确的。所以，如果我测量两个城市之间的距离，然后画出这个圆圈，它就会离开，并且圆圈越大越差。

任何想法？

<script type="text/javascript"> 
function drawCircle(point, radius, dir) { 
var d2r = Math.PI/180; // degrees to radians 
var r2d = 180/Math.PI; // radians to degrees 
var earthsradius = 3959; // 3959 is the radius of the earth in SM 

    var points = 1000; 

    // find the raidus in lat/lon 
    var rlat = (radius/earthsradius) * r2d; 
    var rlng = rlat/Math.cos(point.lat() * d2r); 


    var extp = new Array(); 
    if (dir==1) {var start=0;var end=points+1} // one extra here makes sure we connect the 
    else  {var start=points+1;var end=0} 
    for (var i=start; (dir==1 ? i < end : i > end); i=i+dir) 
    { 
    var theta = Math.PI * (i/(points/2)); 
    ey = point.lng() + (rlng * Math.cos(theta)); // center a + radius x * cos(theta) 
    ex = point.lat() + (rlat * Math.sin(theta)); // center b + radius y * sin(theta) 
    extp.push(new google.maps.LatLng(ex, ey)); 
    bounds.extend(extp[extp.length-1]); 
    } 
    // alert(extp.length); 
    return extp; 
    } 

    var map = null; 
    var bounds = null; 

    function initialize() { 
    var myOptions = { 
    zoom: 10, 
    center: new google.maps.LatLng(29.10860062, -95.46209717), 
    mapTypeControl: true, 
    mapTypeControlOptions: {style: google.maps.MapTypeControlStyle.DROPDOWN_MENU}, 
    navigationControl: true, 
    mapTypeId: google.maps.MapTypeId.TERRAIN 
    } 
    map = new google.maps.Map(document.getElementById("map_canvas"), 
          myOptions); 

    bounds = new google.maps.LatLngBounds(); 

    var donut = new google.maps.Polygon({ 
      paths: [triangleCoords = [ 
         new google.maps.LatLng(-87, 120), 
         new google.maps.LatLng(-87, -87), 
         new google.maps.LatLng(-87, 0)], 
        drawCircle(new google.maps.LatLng(29.10860062, -95.46209717), 2000, -1)],"; 

      strokeColor: "#000000", 
      strokeOpacity: 0.6, 
      strokeWeight: 2, 
      fillColor: "#999999", 
      fillOpacity: 0.6 
}); 
donut.setMap(map); 

map.fitBounds(bounds); 


</script> 

Answer 1

更好的圆绘制例程可以通过使用“点从轴承”的计算在http://www.movable-type.co.uk/scripts/latlong.html#destPoint

θ发现是轴承（以弧度为单位，从北顺时针）; d/R是角距离（以弧度为单位），其中，d是所行进的距离，R是地球半径

var lat2 = Math.asin(Math.sin(lat1)*Math.cos(d/R) + 
       Math.cos(lat1)*Math.sin(d/R)*Math.cos(brng)); 
var lon2 = lon1 + Math.atan2(Math.sin(brng)*Math.sin(d/R)*Math.cos(lat1), 
        Math.cos(d/R)-Math.sin(lat1)*Math.sin(lat2)); 

转换一切为弧度，并确保d和R在相同的单位均表示，我们得到了一个圆圈绘制函数这样

function drawCircle(point, radius, dir, addtoBounds) { 
var d2r = Math.PI/180; // degrees to radians 
var r2d = 180/Math.PI; // radians to degrees 
var earthsradius = 6371000; // 3959 is the radius of the earth in SM 

    var points = 1000; 

    // find the raidus in lat/lon 
    var rlat = (radius/earthsradius) * r2d; 
    var rlng = rlat/Math.cos(point.lat() * d2r); 


    var extp = new Array(); 
    if (dir==1) {var start=0;var end=points+1} // one extra here makes sure we connect the 
    else  {var start=points+1;var end=0} 
    for (var i=start; (dir==1 ? i < end : i > end); i=i+dir) 
    { 
     var theta = Math.PI * (i/(points/2)); 
    var lat1=point.lat()*d2r; 
    var lon1=point.lng()*d2r; 
    var d=radius; 
    var R=earthsradius; 

    var ex = Math.asin(Math.sin(lat1)*Math.cos(d/R) + 
       Math.cos(lat1)*Math.sin(d/R)*Math.cos(theta)); 
    var ey = lon1 + Math.atan2(Math.sin(theta)*Math.sin(d/R)*Math.cos(lat1), 
        Math.cos(d/R)-Math.sin(lat1)*Math.sin(ex)); 
     extp.push(new google.maps.LatLng(ex*r2d, ey*r2d)); 
     if (addtoBounds) bounds.extend(extp[extp.length-1]); 
    } 
    // alert(extp.length); 
    return extp; 
    } 

我有一个例子，在http://www.acleach.me.uk/gmaps/v3/mapsearch.htm，其中中心在CYQX并有在EINN最近另一个标记和1715NM半径的圆（表示为3176180米）。其他圈已增加在500,1000,1500,2000和2500NM的半径。

我也在两点之间添加了测地线。如预期的那样，这以正确的角度交叉圆圈，这是对圆圈计算精度的检查。