2017-10-20 102 views
0

我意识到已经有很多问题询问有关此异常消息的问题,但我已经阅读了它们,所提供的修补程序没有帮助,并且失败解决我的情况:在使用类层次结构和歧视时遇到这个异常信息。我使用休眠5个注释和获得对初始化以下异常(请原谅我的类/变量名称混淆和我在龙目岛的注释评论,柜面你不熟悉的龙目岛):如何正确映射我的类(通过映射引用未知目标实体属性)

org.hibernate作为.AnnotationException:引用的mappedBy未知 目标实体属性: com.example.entity.Ca在 com.example.entity.A.cs

下面是我的类(与不相关的字段中删除)

@Entity 
@Data // generates getters/setters for all fields 
@Builder 
@NoArgsConstructor 
@AllArgsConstructor 
public class A implements Persistable<String> { 
    @Id 
    @NonNull 
    private String id; 

    @NonNull 
    @OneToMany(mappedBy = "a", orphanRemoval = true, cascade = PERSIST) 
    private Set<C> cs; 
} 

@Data //generates getters/setters for all fields as well as toString, equals, and hashCode implementations 
@Entity 
@NoArgsConstructor //generates a no args constructor (required by hibernate) 
@AllArgsConstructor //generates a constructor with all fields present 
@DiscriminatorColumn(discriminatorType = INTEGER, name = B.DISCRIMINATOR_NAME) 
public abstract class B implements Persistable<UUID> { 

    protected static final String DISCRIMINATOR_NAME = "direction"; 
    protected static final String DISCRIMINATOR_1_VALUE = "1"; 
    protected static final String DISCRIMINATOR_1_VALUE = "2"; 

    @Id 
    @GeneratedValue 
    @Column(columnDefinition = "uuid") 
    private UUID id; 

    @NonNull 
    @ManyToOne(optional = false) 
    @JoinColumn(nullable = false, updatable = false) 
    private A a; 
} 

@Entity 
@NoArgsConstructor //generates a no args constructor (required by hibernate) 
@ToString(callSuper = true) //generates toString method which calls super.toString 
@EqualsAndHashCode(callSuper = true) //generates equals and hashCode methods which call their respective methods in the super class 
@DiscriminatorValue(B.SEND_DISCRIMINATOR_VALUE) 
public class C extends B { 

} 

那么,我做错了什么?尽我所知,一切都设置正确。

+0

如何使''属性'受保护'而不是'私人'? – Ish

+0

@Ish没有效果:( –

回答

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经过仔细观察,我可以看到您需要将您的抽象类映射为@MappedSuperclass而不是@Entity以便使映射工作。

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但是C有从B继承的属性的getter和setter ...应该就足够了吧?无论如何,我尝试将它添加到C但它并没有帮助 –

+1

但是B不是'@ MappedSupertype'它应该是@Inntity – Antoniossss

+0

感谢@Antoniossss,这正是我所需要的。请随时更新您的答案,建议使用'@ MappedSuperclass'并将其标记为正确答案。 –