将一个换行符添加到C中的字符串中＃

Question

我有一个字符串。

string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@"; 

我需要在每个字符串中出现“@”符号后添加一个换行符。

我的输出应该是这样的

fkdfdsfdflkdkfk@ 
dfsdfjk72388389@ 
kdkfkdfkkl@ 
jkdjkfjd@ 
jjjk@ 

Answer 1

string text = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@"; 

text = text.Replace("@", "@" + System.Environment.NewLine); 

Answer 2

你可以像这样的@符号后添加一个新行字符：

string newString = oldString.Replace("@", "@\n"); 

您也可以使用NewLine属性的Environment类（我认为它是环境）。

Answer 3

一个简单的字符串替换将完成这项工作。看看下面的例子程序：

using System; 

namespace NewLineThingy 
{ 
    class Program 
    { 
     static void Main(string[] args) 
     { 
      string str = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@"; 
      str = str.Replace("@", "@" + Environment.NewLine); 
      Console.WriteLine(str); 
      Console.ReadKey(); 
     } 
    } 
} 

Answer 4

以前的答案接近，但满足了@符号贴近，你会想，要成为str.Replace("@", "@" + System.Environment.NewLine)实际需求。这将保持@符号并为当前平台添加适当的换行符。

Answer 5

然后，只需修改前面的答案：

Console.Write(strToProcess.Replace("@", "@" + Environment.Newline)); 

如果你不需要想在文本文件中的换行，然后不保存它。

Answer 6

根据你对其他人的回复，类似这样的事情就是你要找的。

string file = @"C:\file.txt"; 
string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@"; 
string[] lines = strToProcess.Split(new char[] { '@' }, StringSplitOptions.RemoveEmptyEntries); 

using (StreamWriter writer = new StreamWriter(file)) 
{ 
    foreach (string line in lines) 
    { 
     writer.WriteLine(line + "@"); 
    } 
} 

Answer 7

正如其他人所说的新行字符将在Windows中的文本文件中给你一个新的行。 尝试以下操作：

using System; 
using System.IO; 

static class Program 
{ 
    static void Main() 
    { 
     WriteToFile 
     (
     @"C:\test.txt", 
     "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@", 
     "@" 
     ); 

     /* 
     output in test.txt in windows = 
     fkdfdsfdflkdkfk@ 
     dfsdfjk72388389@ 
     kdkfkdfkkl@ 
     jkdjkfjd@ 
     jjjk@ 
     */ 
    } 

    public static void WriteToFile(string filename, string text, string newLineDelim) 
    { 
     bool equal = Environment.NewLine == "\r\n"; 

     //Environment.NewLine == \r\n = True 
     Console.WriteLine("Environment.NewLine == \\r\\n = {0}", equal); 

     //replace newLineDelim with newLineDelim + a new line 
     //trim to get rid of any new lines chars at the end of the file 
     string filetext = text.Replace(newLineDelim, newLineDelim + Environment.NewLine).Trim(); 

     using (StreamWriter sw = new StreamWriter(File.OpenWrite(filename))) 
     { 
      sw.Write(filetext); 
     } 
    } 
} 

Answer 8

string str = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@"; 
str = str.Replace("@", Environment.NewLine); 
richTextBox1.Text = str; 

Answer 9

你也可以使用string[] something = text.Split('@')。确保您使用单引号将“@”包围起来以将其存储为char类型。 这将字符存储直至并包括每个“@”作为阵列中的各个字。然后，您可以输出的每个（element + System.Environment.NewLine）使用for循环或将其写入使用System.IO.File.WriteAllLines([file path + name and extension], [array name])一个文本文件。如果指定的文件不存在于该位置，它将自动创建。

Answer 10

protected void Button1_Click(object sender, EventArgs e) 
{ 
    string str = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@"; 
    str = str.Replace("@", "@" + "<br/>"); 
    Response.Write(str);  
} 

Answer 11

using System; 
using System.IO; 
using System.Text; 

class Test 
{ 
    public static void Main() 
    { 
      string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@"; 
      strToProcess.Replace("@", Environment.NewLine); 
      Console.WriteLine(strToProcess); 
    } 
} 

Answer 12

string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@"; 
var result = strToProcess.Replace("@", "@ \r\n"); 
Console.WriteLine(result); 

Output