斜杠我得到这个变量:PHP中添加字符串
$payments['date'] = 21062013
问题:
它的日期,所以我想斜线添加到该字符串。
如何我想:
echo $paymentdate = substr($payments['date'],2)+/+substr($payments['date'],4)+/substr($payments['date'],8);
它不工作,可以有一个人帮助吗?
我全码:
$i = 0;
foreach($SQL->query('SELECT id, form, email, value, data, date, compensated from payments where compensated="N"') as $payments)
{
$i++;
$paymentdate = substr($payments['date'], 0, 2)."/".substr($payments['date'], 2, 2)."/".substr($payments['date'], 2, 8);
echo '<tr bgcolor="' . (is_int($i/2) ? $config['site']['darkborder'] : $config['site']['lightborder']) . '">
<td>' . $payments['id'] . '</td>
<td>' . $payments['form'] . '</td>
<td>' . $payments['email'] . '</td>
<td>' . $payments['value'] . '</td>
<td>' . $paymentdate .'</td>
<td>' . $payments['data'] . '</td>
<td>' . $payments['compensated'] . '</td>
<td>a</td>
</tr>';
}
加入字符串使用'.'例如:'回声$ string1.function() “字符串” $ another_variable;'' – Kyslik
回波$ PAYMENTDATE = SUBSTR($付款[。 '日期'],2)。 '/'。 substr($ payments ['date'],4)。 '/'。 substr($ payments ['date'],8);' – hek2mgl