执行内部函数,我想执行的内部功能,但我很努力理解为什么回来为未定义通过返回函数名
object.method2();
var object = {
method1 : function(){
return function(){
innerFunction();
}
},
method2 : function(){
function innerFunction(){
alert('I am showing as not defined but I want to be executed')
}
executeInnerFunction = object.method1()
executeInnerFunction();
}
}
+1代码示例 – Tom