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以下是存储过程中返回记录的SQL语句正常。但是,我也需要MEMBER_ID的值。当我将它添加到select语句中时,不会返回任何记录。我尝试了CAST和CONVERT,但没有结果。作为参考,MEMBER_ID字段是两个表中的关键值。这是一个INT。SQL语句问题
SELECT
CONCAT(WEBFSS.MEMBERS.LAST_NAME, ", " ,WEBFSS.MEMBERS.FIRST_NAME) As Name,
SUM(CASE WHEN WEBFSS.SCHEDULE.DATE = _mon THEN WEBFSS.SCHEDULE.QTY END) AS MEALS1,
SUM(CASE WHEN WEBFSS.SCHEDULE.DATE = _mon THEN WEBFSS.SCHEDULE.ENSURE END) AS ENS1,
SUM(CASE WHEN WEBFSS.SCHEDULE.DATE = _tue THEN WEBFSS.SCHEDULE.QTY END) AS MEALS2,
SUM(CASE WHEN WEBFSS.SCHEDULE.DATE = _tue THEN WEBFSS.SCHEDULE.ENSURE END) AS ENS2,
SUM(CASE WHEN WEBFSS.SCHEDULE.DATE = _wed THEN WEBFSS.SCHEDULE.QTY END) AS MEALS3,
SUM(CASE WHEN WEBFSS.SCHEDULE.DATE = _wed THEN WEBFSS.SCHEDULE.ENSURE END) AS ENS3,
SUM(CASE WHEN WEBFSS.SCHEDULE.DATE = _thu THEN WEBFSS.SCHEDULE.QTY END) AS MEALS4,
SUM(CASE WHEN WEBFSS.SCHEDULE.DATE = _thu THEN WEBFSS.SCHEDULE.ENSURE END) AS ENS4,
SUM(CASE WHEN WEBFSS.SCHEDULE.DATE = _fri THEN WEBFSS.SCHEDULE.QTY END) AS MEALS5,
SUM(CASE WHEN WEBFSS.SCHEDULE.DATE = _fri THEN WEBFSS.SCHEDULE.ENSURE END) AS ENS5
FROM WEBFSS.SCHEDULE
INNER JOIN WEBFSS.MEMBERS
ON WEBFSS.SCHEDULE.MEMBER_ID = WEBFSS.MEMBERS.MEMBER_ID
WHERE
(WEBFSS.SCHEDULE.DATE BETWEEN _mon AND _fri)
GROUP BY
WEBFSS.MEMBERS.LAST_NAME, WEBFSS.MEMBERS.FIRST_NAME ;
这不起作用:
SELECT
SCHEUDLE.MEMBER_ID,
CONCAT(WEBFSS.MEMBERS.LAST_NAME, ", " ,WEBFSS.MEMBERS.FIRST_NAME) As Name,
SUM(CASE WHEN WEBFSS.SCHEDULE.DATE = _mon THEN WEBFSS.SCHEDULE.QTY END) AS MEALS1,
“'SCHEUDLE'”?看起来你只是拼错了你的表名。但是也许你在写这篇文章时错误地输入了它。将来,请使用复制和粘贴来避免此类错误。 –
如果您遇到错误,请在您的帖子中包含完整的错误消息。 –