我有关于在Java Spring中获取某些特定列的问题。
我正在使用Java Spring Boot和GraphDB作为我的数据库,并使用Model和Repository访问数据库(例如:我有userRepository,并使用userRepository.FindAll,并且所有记录都在其所有字段中加载)。
举例来说,我有一个列/字段的表:如何使用Neo4j从存储库获取特定列
@NodeEntity
public class User {
@GraphId
Long id;
@NotNull
@Indexed(unique=true)
private String username;
@NotNull
private String password;
@NotNull
private String firstName;
@NotNull
private String lastName;
@NotNull
private String role;
@NotNull
private Boolean active;
public User() {
}
public User(String username, String password, String firstName,
String lastName, String role, Boolean active) {
super();
this.username = username;
this.password = password;
this.firstName = firstName;
this.lastName = lastName;
this.role = role;
this.active = active;
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public String getRole() {
return role;
}
public void setRole(String role) {
this.role = role;
}
public Boolean getActive() {
return active;
}
public void setActive(Boolean active) {
this.active = active;
}
}
随着存储库这样的:
public interface UserRepository extends GraphRepository<User> {
}
我没有把UserRepository.FindAll,因为它已经实现了它GraphRepository
我不需要加载“密码”字段。我应该如何在不加载“密码”字段的情况下加载记录?
你说我需要用@QueryResult创建类。据我所知,1类= 1文件类。如果我需要很多这样的查询,我是否必须创建许多文件? – 2015-02-24 03:59:00
我可以通过ID吗? @Query(“MATCH(u:USER)RETURN u.id as id,u.username as username,u.role as role”) 我无法获取ID – 2015-02-24 07:27:22
我已经编辑了我的答案和其他信息。 – 2015-02-24 08:30:26