LINQ/Lambda更新通过将项目拆分成偶数组来列出项目

Question

应用程序的一些背景。这是针对我拥有的WASP和SMPP发射器帐户。

我有一个列表<>它包含一个对象，该对象具有SMPP PDU的所有必需对象并发送消息。 此列表包含名为“路由标签”的属性，路由标签将指示哪个服务提供商将PDU提交给（Vodacom，MTN，Cell C）。

我有另一个帐户列表，我可以绑定到SMPP服务器并发送消息。该列表还包含路由标签并且具有发射器帐户的名称。因此，例如Vodacom的路由标签是“D082”，我有两个帐户可以同时绑定。

我现在需要采取第一个清单<>并更新字段。可以说第一个列表<>有1000个项目。我需要将这些（或多或少均匀地）分配给我提到的第二个列表<>中出现的每个“路由标签”的所有帐户。

我宁愿使用linq或lambda来实现所需的功能。

=====编辑：添加代码示例，以便您善良的人可以帮助我:-)对不起，标准很差，但我快速剥离了一些代码给你们。我希望这有助于我的问题。

static void Main(string[] args) 
    { 


     List<MobileAccounts> TransmitterAccounts = new List<MobileAccounts>();//This list contains my transmitter accounts 


     MobileAccounts item = new MobileAccounts(); 
     item.FriendlyName = "Vodacom 1"; 
     item.RoutingLabel = "D082"; 
     TransmitterAccounts.Add(item); 

     MobileAccounts item1 = new MobileAccounts(); 
     item1.FriendlyName = "Vodacom 2"; 
     item1.RoutingLabel = "D082"; 
     TransmitterAccounts.Add(item1); 


     MobileAccounts item2 = new MobileAccounts(); 
     item2.FriendlyName = "MTN 1"; 
     item2.RoutingLabel = "D083"; 
     TransmitterAccounts.Add(item2); 


     MobileAccounts item3 = new MobileAccounts(); 
     item3.FriendlyName = "MTN 2"; 
     item3.RoutingLabel = "D083"; 
     TransmitterAccounts.Add(item3); 

     MobileAccounts item4 = new MobileAccounts(); 
     item4.FriendlyName = "MTN 3"; 
     item4.RoutingLabel = "D083"; 
     TransmitterAccounts.Add(item4); 

     MobileAccounts item5 = new MobileAccounts(); 
     item5.FriendlyName = "CellC 1"; 
     item5.RoutingLabel = "D084"; 
     TransmitterAccounts.Add(item5); 

     MobileAccounts item6 = new MobileAccounts(); 
     item6.FriendlyName = "CellC 2"; 
     item6.RoutingLabel = "D084"; 
     TransmitterAccounts.Add(item6); 


     List<SubmitSm> col = new List<SubmitSm>();//this list contains messages in a queue ready for sending 

     SubmitSm sitem = new SubmitSm(); 
     sitem.DestAddr = "0722222222";//Vodacom number 
     sitem.RoutingLabel = "D082"; 
     col.Add(sitem); 

     SubmitSm sitem1 = new SubmitSm(); 
     sitem1.DestAddr = "0722222220";//Vodacom number 
     sitem1.RoutingLabel = "D082"; 
     col.Add(sitem1); 

     SubmitSm sitem2 = new SubmitSm(); 
     sitem2.DestAddr = "0722221212";//Vodacom number 
     sitem2.RoutingLabel = "D082"; 
     col.Add(sitem2); 

     SubmitSm sitem3 = new SubmitSm(); 
     sitem3.DestAddr = "0830000000";//MTN number 
     sitem3.RoutingLabel = "D083"; 
     col.Add(sitem3); 


     SubmitSm sitem4 = new SubmitSm(); 
     sitem4.DestAddr = "0833746005";//MTN number 
     sitem4.RoutingLabel = "D083"; 
     col.Add(sitem4); 

     SubmitSm sitem5 = new SubmitSm(); 
     sitem5.DestAddr = "0749999998";//CellC number 
     sitem5.RoutingLabel = "D084"; 
     col.Add(sitem5); 

     /* 
     * Now this is where I will need 
     * to split all the messages in "col" 
     * amongst all the transmitter accounts 
     * I have. 
     */ 


    } 

public class MobileAccounts 
{ 
    /*Please note not all items 
    are in this class. I have 
    * removed some as they are not 
    * neccessary for this demo code.    
    */ 

    //[DataMember] 
    public string FriendlyName; 

    //[DataMember] 
    public string BindName; 

    //[DataMember] 
    public string BindPassword; 

    //[DataMember] 
    public string BindHost; 

    //[DataMember] 
    public string BindPort; 

    //[DataMember] 
    public string BindType; 

    //[DataMember] 
    public string ProviderCode; 

    //[DataMember] 
    public string RoutingLabel; 


} 

public class SubmitSm 
{ 
    /*Please note not all items 
    are in this class. I have 
    * removed some as they are not 
    * neccessary for this demo code.    
    */ 
    public byte DefaultMessageId { get; set; } 

    public string DestAddr { get; set; } 

    public byte DestAddrNpi { get; set; } 

    public byte DestAddrTon { get; set; } 

    public string MessageText { get; set; }   

    public byte PriorityFlag { get; set; } 

    public byte ProtocolId { get; set; } 

    public byte RegisteredDelivery { get; set; }     

    public string ScheduleDeliveryTime { get; set; } 

    public string ServiceType { get; set; } 

    public string SourceAddr { get; set; } 

    public byte SourceAddrNpi { get; set; } 

    public byte SourceAddrTon { get; set; } 

    public string ValidityPeriod { get; set; } 

    public string RoutingLabel { get; set; } 

} 

谢谢大家的贡献。 @NinjaNye你的解决方案很近，但并不完全符合我的要求。尽管如此，我很欣赏你的努力。

我认为我几乎在那里，但我挣扎。有人可以帮助我找出如下所示的子选择：

List<IGrouping<string, MobileAccounts>> sad1 = TransmitterAccounts.GroupBy(y => y.RoutingLabel).ToList(); 
col = (List<SubmitSm>)col.Select 
           (x => 
            { 
             x.ServiceType = sad1.Where 
                   (z => 
                    z.Key==  x.ServiceType 
                     )              
                     .Select 
                      (y => 
                        new 
                        { 
                         //this should return the Transmitter account that has the lowest count 

                         TransmitterAccount = y.OrderBy(ui => x.ServiceType.Count()).Select(ui => ui.FriendlyName).First() 
                        } 
                      ).First().TransmitterAccount;             

               return x; 
             } 
            ).ToList(); 

Answer 1

唯一使用LINQ的，我可以看到这里可能是使用的.Skip()和.Take()但是我已经创建了一个扩展方法来整理了一点东西。这意味着你可以简单地写下面的内容来拆分任何IEnumerable。

// In your example above you need to replace `items` with your `col` variable 
var result = items.Split(transmitter.Count()); 

扩展方法

http://www.ninjanye.co.uk/2013/07/splitting-distributing-list-objects.html

http://jnye.co/Posts/10/evenly-splitting-distributing-a-list-of-objects-using-linq-and-extension-methods

public static class EnumerableExtensions 
{ 
    public static IEnumerable<IEnumerable<T>> Split<T>(this IEnumerable<T> source, int groups) 
    { 
     var listedSource = source.ToList(); 
     int extra; 
     int groupSize = Math.DivRem(listedSource.Count(), groups, out extra); 

     while (listedSource.Any()) 
     { 
      int newSize = groupSize; 
      if (extra > 0) 
      { 
       newSize++; 
       extra--; 
      } 
      yield return listedSource.Take(newSize); 
      listedSource = listedSource.Skip(newSize).ToList(); 
     } 
    } 
} 

结果

我设置此起来作为一个快速的命令程序来测试

这里有一些成果，所以你可以看到项目拆分：

战后初期（现上述重构）

像这样的东西应该做的它...不过我已经简化的例子

 // This is your transmitter count 
     int groups = 4; 
     // These are your SMS's 
     List<int> values = new List<int>(){1,2,3,4,5,6,7,8,9}; 

     //Calculate group size 
     int extra; 
     int groupSize = Math.DivRem(values.Count, groups, out extra); 

     var result = new List<IEnumerable<int>>(); 
     while (values.Any()) 
     { 
      int newSize = groupSize; 
      if (extra > 0) 
      { 
       // Account for extras 
       newSize++; 
       extra--; 
      } 
      result.Add(values.Take(newSize)); 
      values = values.Skip(newSize).ToList(); 
     } 

     return result; 

Answer 2

你应该避免带有副作用的LINQ。但是你可以将对象附加到列表中。

 List<MobileAccounts> mas = new List<MobileAccounts>(); 
     List<SubmitSm> sms = new List<SubmitSm>(); 

     var result = mas.Select(ma => new {Sm=(sms.First(sm => sm.RoutingLabel == ma.RoutingLabel)),Ma=ma}); 
     foreach (var r in result) 
     { 
      //update Properties here 
     }