我有一个查询获取有关特定作业的一些信息。显示前1最大列
但是,我努力获得每项工作的最高记录(基于最新的'LastRun'字段)。
任何帮助我如何实现这一目标?
我的查询是:
SELECT
job.Name,
CAST(CAST(hist.run_date AS CHAR(8))
+ ' '
+ STUFF(
STUFF(RIGHT('000000' + CAST(hist.run_time AS VARCHAR(6)), 6)
, 3, 0, ':')
, 6, 0, ':')
AS DATETIME) AS LastRun,
CASE hist.run_status
WHEN 0 THEN 'Failed'
WHEN 1 THEN 'Success'
WHEN 2 THEN 'Retry'
WHEN 3 THEN 'Canceled'
WHEN 4 THEN 'In progress'
END AS Status,
CASE job.enabled
WHEN 0 THEN 'False'
WHEN 1 THEN 'True'
END AS Enabled
FROM dbo.sysjobhistory hist
JOIN dbo.sysjobs_view job ON job.job_id=hist.job_id
WHERE job.[name] = '[Parallel] Copy DBOutboxMaster'
OR job.[name] = '[Parallel] Copy filestore to PPE'
OR job.[name] = '[Parallel] copyLogShippingForECW'
OR job.[name] = '[Parallel] copyLogShippingForNLASQL'
GROUP BY job.name,hist.run_date,hist.run_time,hist.run_status,job.enabled
ORDER BY lastrun DESC
我目前得到的结果:
[Parallel] Copy DBOutboxMaster 2017-10-20 09:32:00.000 Success True
[Parallel] Copy filestore to PPE 2017-10-20 09:32:00.000 Success True
[Parallel] copyLogShippingForECW 2017-10-20 09:32:00.000 Success True
[Parallel] copyLogShippingForNLASQL 2017-10-20 09:31:11.000 Success True
[Parallel] Copy DBOutboxMaster 2017-10-20 09:31:00.000 Success True
正如你可以看到有每个作业重复字段。我只想每个工作的最高记录,所以总共应该只有4个最新LastRun日期时间的结果
我不明白你的复制作业在哪里 –
从group by中删除hist.run_time,在select中将其更改为max(或min?)(hist.run_time)。那工作? –
@RyanGadsdon查看结果中的第一条记录和最后一条记录。他们是一样的工作 – Bodz