总和（或计数）多个case语句

Question

我有如下表：

Month | Item | Events | Party | Spirit | Faith | 
May | 123 | 1 | 1 | 0 | 0 | 
June |123 | 1 | 0 | 1 | 1 | 

它基本上是1是0否。我需要知道每个项目多少不同的类别是每个月

我需要的结果如下：

Month | Item | Counts | 
May | 123 | 2 | 
June| 123 | 3 | 

这是行不通的：

select Month, Item, 
     sum(case when EVENTS = 1 then 1 when PARTY = 1 then 1 when SPIRIT = 1 then 1 when FAITH = 1 then 1 else 0 end) as Counts 
from TABLE 
group by 1,2 

请帮帮忙，谢谢！

Answer 1

你并不需要聚集：不需要

select Month, Item, 
     (events + party + spirit + faith) as counts 
from t; 

Answer 2

CREATE TABLE #T 
(
Month varchar(10), Item int, Events bit, Party bit, Spirit bit , Faith bit 
) 
insert into #T 
SELECT 'May' , 123 , 1 , 1 , 0 , 0 union 
SELECT 'June' ,123 , 1 , 0 , 1 , 1 

select Month, Item, CAST(Events AS INT) + CAST(Party AS INT)+ CAST(Spirit AS 
INT) +CAST(Faith AS INT) from #T 

聚集。由于事件，派对，精神和信仰都是位列，所以我们需要将它投射到int然后添加它。