字母序列生成的SQL Server

Question

我试图生成一系列字母的，使用SQL Server。

假设我有一个表如下

DECLARE @Funding TABLE (FundingDetailID INT,FundingID INT, DetailDescription VARCHAR(50)) 
INSERT INTO @Funding (FundingDetailID ,FundingID , DetailDescription) VALUES (1,107,'Desc 1') 
INSERT INTO @Funding (FundingDetailID ,FundingID , DetailDescription) VALUES (1,107,'Desc 2') 
INSERT INTO @Funding (FundingDetailID ,FundingID , DetailDescription) VALUES (1,107,'Desc 3') 

我试图得到下面的结果。

a) Desc 1 
b) Desc 2 
c) Desc 3 

如何生成“a)”, “b)”, ...？我不允许添加任何额外的临时表或表变量来存储最初的字母。它们应该被生成。

这是要在SQL Server 2005中完成的。

有什么想法？

感谢

Lijo Cheeran约瑟夫

Answer 1

使用ROW_NUMBER（）如下

DECLARE @Funding TABLE (FundingDetailID INT,FundingID INT, DetailDescription VARCHAR(50)) 
INSERT INTO @Funding VALUES (1,107,'Desc 1') 
INSERT INTO @Funding VALUES (1,107,'Desc 2') 
INSERT INTO @Funding VALUES (1,107,'Desc 3') 

SELECT CHAR (CAST (96+ROW_NUMBER() OVER (Order BY FundingDetailID) AS VARCHAR)) + ') ' + DetailDescription 
FROM @Funding 



----------------------------------------------------- 
a) Desc 1 
b) Desc 2 
c) Desc 3 

Answer 2

拉吉更已经发布的row_number()，而我写它。我投了他的答案，但这是我的变种，在桌子上做了更新，以防万一你对此感兴趣。

update f1 
set  f1.DetailDescription = char(96 + f2.rn) + ') ' + f2.DetailDescription 
from @Funding f1 
join (
     select row_number() over (order by FundingDetailId, 
             FundingId, DetailDescription) as rn 
     ,  * 
     from @Funding f 
     ) f2 
on  f1.FundingDetailID = f2.FundingDetailID 
     and f1.FundingID = f2.FundingID 
     and f1.DetailDescription = f2.DetailDescription 

select * 
from @Funding