我不认为这有问题,但是有没有办法将多层次,不均匀结构的列表信息合并为一个“长”格式的数据帧?将不均匀的分层列表转换为数据帧
具体来说:
library(XML)
library(plyr)
xml.inning <- "http://gd2.mlb.com/components/game/mlb/year_2009/month_05/day_02/gid_2009_05_02_chamlb_texmlb_1/inning/inning_5.xml"
xml.parse <- xmlInternalTreeParse(xml.inning)
xml.list <- xmlToList(xml.parse)
## $top$atbat
## $top$atbat$pitch
## des id type x y
## "Ball" "310" "B" "70.39" "125.20"
凡下面是结构:
> llply(xml.list, function(x) llply(x, function(x) table(names(x))))
$top
$top$atbat
.attrs pitch
1 4
$top$atbat
.attrs pitch
1 4
$top$atbat
.attrs pitch
1 5
$bottom
$bottom$action
b des event o pitch player s
1 1 1 1 1 1 1
$bottom$atbat
.attrs pitch
1 5
$bottom$atbat
.attrs pitch
1 5
$bottom$atbat
.attrs pitch runner
1 5 1
$bottom$atbat
.attrs pitch runner
1 7 1
$.attrs
$.attrs$num
character(0)
$.attrs$away_team
character(0)
$.attrs$
我想是有从命名矢量从间距类别的数据帧,沿着(top,atbat,bottom)。因此,由于列数不同,我需要忽略不适合data.frame的级别。事情是这样的:
first second third des x
1 top atbat pitch Ball 70.29
2 top atbat pitch Strike 69.24
3 bottom atbat pitch Out 67.22
是否有这样做的一个优雅的方式?谢谢!
相关问题:http://stackoverflow.com/questions/2067098/how-to-transform-xml-data-into-a-data-frame – apeescape 2010-08-05 19:00:31