检查多个列进行重复并列出所有记录

Question

我有一个列ID，内容和日期的表。我想找到有重复的内容和日值的所有行和显示所有行

SELECT ID,Content, `Day`, Count(*) 
FROM table 
GROUP BY Content,`Day` 
HAVING COUNT(*) > 1 

当前的代码将返回重复的内容的列表和“日”的值，例如：

ID|Content|Day 
1 | a | 1 
2 | a | 1 
3 | a | 1 
4 | b | 2 
5 | b | 2 
6 | c | 3 
7 | c | 4 

会导致：

ID|Content|Day|Count 
1 | a | 1 | 3 
4 | b | 2 | 2 

但我要显示所有的唯一ID为好;

ID|Content|Day 
1 | a | 1 
2 | a | 1 
3 | a | 1 
4 | b | 2 
5 | b | 2 

Answer 1

只是做一个Sub-Query

select * 
from table 
where `day` in 
( 
SELECT ID 
FROM table 
GROUP BY Content,`Day` 
HAVING COUNT(*) > 1 
) A 

Answer 2

使用它作为一个子查询的加盟对表再次查询： -

SELECT table.ID, table.Content, table.`Day` 
FROM table 
INNER JOIN 
(
    SELECT Content, `Day`, Count(*) 
    FROM table 
    GROUP BY Content,`Day` 
    HAVING COUNT(*) > 1 
) sub0 
ON sub0.Content = table.Content 
AND sub0.`Day` = table.`Day`