使用AWK
$awk -F"_" 'function print_array(arr,max){ for(i=1; i<=max; i++) if(a[i]){print a[i], a[i]="";} } key==$5{a[$8]=$0; key=$5; max=$8>max?$8:max} key!=$5{print_array(a,max); key=$5; a[$8]=$0; max=$8} END{print_array(a,max)}' file
输出:
abc_bla_bla_bla_reg0_bla_reg_1_0
abc_bla_bla_bla_reg0_bla_reg_2_0
abc_bla_bla_bla_reg0_bla_reg_5_0
abc_bla_bla_bla_reg0_bla_reg_10_0
abc_bla_bla_bla_reg0_bla_reg_15_0
abc_bla_bla_bla_reg2_bla_reg_7_0
abc_bla_bla_bla_reg2_bla_reg_9_0
abc_bla_bla_bla_reg2_bla_reg_15_0
abc_bla_bla_bla_reg3_bla_reg_3_0
abc_bla_bla_bla_reg3_bla_reg_5_0
abc_bla_bla_bla_reg3_bla_reg_26_0
说明:
awk -F"_" '
function print_array(arr,max) #Simply prints the hashed array from i=1 to max value array is holding
{
for(i=1; i<=max; i++)
if(a[i])
{print a[i], a[i]="";}
}
key==$5{a[$8]=$0; max=$8>max?$8:max} #Key here denotes the 5th field for eg. reg0 in line one. Initially key is null and it will satisfy the condition mentioned below i.e key!=$5. If the 5th field matches with the key set in previous line then push the record into array where the index in array will be the value at field 8 based on which you want to sort your results.
key!=$5{print_array(a,max); key=$5; a[$8]=$0; max=$8} #If key doesn't matches the 5th line it signifies we have a new record set and before proceeding further print the array we stored for previous record set based on 5th field.
END{print_array(a,max) #To print the last record set
}' file
key==$5{a[$8]=$0; max=$8>max?$8:max}
:Key
这里表示例如第5个字段。第一行是reg0
。起初key
为空,它将满足下面提到的条件,即key!=$5
。如果第五个字段$5
与前一行中设置的键匹配,则将该记录推入数组,其中索引在数组中将成为字段8的值,根据此值对结果进行排序。无论$8
中的位数是多少,这都可以工作。
key!=$5{print_array(a,max); key=$5; a[$8]=$0; max=$8}
如果key
与第5行不匹配,则表示我们有一个新的记录集,然后再继续打印基于第5个字段存储的先前记录集的数组。
END{print_array(a,max)
只是为了打印最后一个记录集
感谢你很多 它的完美的工作! – Lucil120