我用简单的验证PHP程序的工作,我有2个文件,1个用于显示和1个控制这些都是我的代码:总是返回一个声明
<form action="comp.php" method="post">
<input type="text" name="reading" placeholder="kilometer reading">
<input type="date" name="date1" placeholder="date">
<input type="text" name="suggest" placeholder="suggested kilometer">
<input type="text" name="part" placeholder="spare part">
<input type="submit" class="button" name="btnsubmit" value="Submit">
</form>
,这是对我的控制:
$date1 = date('Y-m-d', strtotime($_POST['date1']));
$reading = $_POST['reading'];
$suggest = $_POST['suggest'];
$part =$_POST['part'];
$sql = "SELECT reading FROM sched ORDER BY reading DESC LIMIT 1";
$result = mysqli_query($sqli, $sql);
if (empty($_POST['reading']))
{
echo "No Input ";
exit;
}
elseif ($_POST['reading'] < $result)
{
echo "Must input higher value than";
exit;
}
elseif ($_POST['reading'] > $result)
{
if (($_POST['date1']) == "1970-01-01")
{
echo "no date input";
exit;
}
else
{
$query = mysqli_query($sqli,"INSERT INTO sched (date,reading,suggest,part) VALUES ('$date1','$reading','$suggest','$part')");
}
}
}
mysqli_close($sqli);
header("Location: log.php");
我目前的最高读数是'15000'。 当我的字段reading
为空时,程序可以正常工作,但是如果我向我的字段输入值,即使输入的值高于15000,也总是返回echo "Must input higher value than"; exit;
.这是什么问题?
如果您尝试获取结果集,将更好地工作,目前'$ result'将等于或者TRUE;或'false'作为mysqli_query()返回查询执行的状态,而不是返回结果集。当所有其他都失败时[阅读Flippin手册](http://php.net/manual/en/function.mysql-query.php) – RiggsFolly
使用提示信息的错误消息是非常好的做法,以'echo'开始您的输入值['。$ _ POST ['reading']。']低于['.result。']';' –